 | William Chauvenet - 1871 - 268 pàgines
...considered, the two sides including it are regarded as adjacent parts. The rules are : I. The tine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. The correctness... | |
 | Edwin Pliny Seaver - 1871 - 78 pàgines
...equations, (175) - (184), may be embodied in the following mnemonic rules : — I. The sine of any part is equal to the product of the tangents of the adjacent parts. II. The sine of any part is equal to the product of the cosines of the opposite parts. (с) SOLUTIONS.... | |
 | Henry William Jeans - 1873 - 292 pàgines
...substituted for cos. со. A ; cos. A for sin. со. A ; cot. A for tan. со. A, to. (See Part II.) EULE B. The sine of the middle part is equal to the product of the cosines -of the two parts opposite to, or separated from it.* Having written down the equation according... | |
 | Aaron Schuyler - 1875 - 284 pàgines
...90°— P, 90°— Л, p. 7. b, 90°— P, p. 8. 90°— B, 90°— Л, b. 9. 90°— A, 90'— P, b. 10. 90°— P, 90°— B, p. 126. Napier's Principles....perpendicular to OH. The angle BED is equal to P. = sin h, OE=cos h, DB = sin p, and OD~cos p. ED OE ED „ = -7ТТГ X -77.-,' or cos P— cot Л tan 6.... | |
 | Horatio Nelson Robinson - 1875 - 288 pàgines
...of the middle part, is equal to the product of the tangents of the adjacent parts. 2d. Radius into the sine of the middle part, is equal to the product of the cosines of the opposite parts. The parts are the two sides, the complements of the hypotenuse, and... | |
 | Benjamin Greenleaf - 1876 - 204 pàgines
...NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the... | |
 | Henry Nathan Wheeler - 1876 - 218 pàgines
...cos a = - — = . sin A sin B cos c = ctn A ctn B. [5] [6] §8. > Napier,s Rules. (1) The sine of any part is equal to the product of the (t)angents of the (a)djacent parts. (2) The sine of any part is equal to the product of the (e)osinesoi the (o)pposite parts. 510. Given... | |
 | Horatio Nelson Robinson - 1878 - 564 pàgines
...that it corresponds to one of the following invariable and comprehensive rides. 1. The radius into the sine of the middle part is equal to the product of the tangents of the adjacent parts. 2. The radius into the sine of the middle part is equal io> the product of the cosines of the opposite... | |
 | Michael McDermott - 1879 - 540 pàgines
...angle. We will arrange Napier's rules as follows, where co. = complement of the angles or hypothenuse. Sine of the middle part, Is equal to the product of the tangents of the adjacent parts. Is equal to the product of the cosines of the opposite parts. Sine comp. A. Sin. comp. c. Sin. comp.... | |
 | Eugene Lamb Richards - 1879 - 232 pàgines
...Parts. The sine of the middle part is equal to the product of the tangents of the adjacent parts; and the sine of the middle part is equal to the product of the cosines of the opposite parts. Let ABC be a spherical triangle right-angled at B. We shall take each... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 
