 | Benjamin Peirce - 1845 - 498 pàgines
...other two parts are called the opposite parts. The two theorems are as follows. Napier's Rules. II. The sine of the middle part is equal to the product of the cosines of the two opposite parts. [B. p. 436.] Proof. To demonstrate the preceding rules, it is only... | |
 | James Hann - 1849 - 84 pàgines
...disjunct. This practical method will be useful to seamen, and requires very little effort of memory. The sine of the middle part, is equal to the product of the cosines of the extremes disjunct. From these two equations, proportions may be formed, observing always... | |
 | Benjamin Peirce - 1852 - 382 pàgines
...parts ; and the other two parts are called the opposite parts. The two theorems are as follows. I. The sine of the middle part is equal to the product of the tangents of the two adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the two... | |
 | William Chauvenet - 1852 - 268 pàgines
...: I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. The correctness of these rules will be shown by taking each of the five... | |
 | Benjamin Peirce - 1852 - 410 pàgines
...sine of the middle part is equal to the product of the tangents of the two adjacent parts. IL TJie sine of the middle part is equal to the product of the cosines of the two opposite parts. [B. p. 436.] Proof. To demonstrate the preceding rules, it is only... | |
 | Elias Loomis - 1855 - 192 pàgines
...part required may then be found by the following RULE OF NAPIER. (211.) The product of the radius and the sine of the middle part, is equal to the product of the tangents of the adjacent parts, or to the product of the cosines of the opposite parts. It will assist the learner in remembering this... | |
 | George Roberts Perkins - 1856 - 460 pàgines
...RULES, I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. If now we take in turn each of the five parts as the middle part, and... | |
 | Henry William Jeans - 1858 - 106 pàgines
...of the middle part is equal to the product of the tangents of the two parts adjacent to it. EULE B. The sine of the middle part is equal to the product of the cosines of the two parts opposite to, or separated from it. Having written down the equation according... | |
 | Elias Loomis - 1859 - 372 pàgines
...part required may then be found by the following RULE OF NAPIER. (211.) The product of the radius and the sine of the middle part, is equal to the product of the tangents of the adjacent parts, or to the product of the cosines of the opposite parts. It will assist the learner in remembering this... | |
 | John Daniel Runkle - 1859 - 478 pàgines
...RULES. BY TUI MAN HENRY 8AFFORD. IN the form in which they are usually given, the rules are — I. The sine of the middle part is equal to the product of tlie tangents of tJie adjacent parts. II. T/te sine of the middle part is equal to tJic product of... | |
| |
I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 
