 | 1860 - 462 pàgines
...RULE I. The sine of the middle pari equals the product of the cosines of the opposite parts. RULE II. The sine of the middle part is equal to the product of the tangents of the adjacent parts. That the second of these rules may be deduced from the first has been shown by Mr. SAFFORD, in No.... | |
 | Horatio Nelson Robinson - 1860 - 470 pàgines
...of the middle part is equal to the product of the tangents of the adjacent parts. 2. The radius into the sine of the middle part is equal to the product of the cosines of the opposite parts. These rules are known as .Napier's Rules, because they were first given... | |
 | George Roberts Perkins - 1860 - 472 pàgines
...RULES. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. If now we take in turn each of the five parts as the middle part, and... | |
 | Elias Loomis - 1862 - 202 pàgines
...required may then be found by the following i RULE OF NAPIER. (211.) The product of the radius and the sine of the middle part, is equal to the product of the t&ngents of the adjacent parts, or to the product of the cosines of the opposite parts. It will assist... | |
 | Benjamin Greenleaf - 1862 - 518 pàgines
...NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the... | |
 | Benjamin Greenleaf - 1862 - 532 pàgines
...NAPIER. I. The sine of the middle part is equal to Hie product of tlte tangents of the adjacent parts. IL The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the... | |
 | Benjamin Greenleaf - 1861 - 638 pàgines
...NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of tJie cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with... | |
 | Benjamin Greenleaf - 1863 - 504 pàgines
...I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. . II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the... | |
 | Gerardus Beekman Docharty - 1867 - 474 pàgines
...stated, we may now give the BULES. 1. M being the middle part, the product of sin. M and tabular radius is equal to the product of the tangents of the adjacent parts. . 2. The product of sin. M and tabular radius is equal to the product of the cosines of the opposite... | |
 | Eli Todd Tappan - 1868 - 444 pàgines
...next to it are the adjacent parts, and the remaining two are the opposite parts. Napier's rule is : The sine of the middle part is equal to the product of the tangents of the adjacent parts, also to the product of the cosines of the opposite parts. The words sine and middle having their first... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 
