 | Chambers W. and R., ltd - 1842 - 744 pàgines
...proposition gives still further information on this useful subject. It shows that if two triangle* have two angles of the one equal to two angles of the other, each to each, and one side equal to one aide, namely, either the sides adjacent to the equal angles, or the sides opposite to... | |
 | 1842 - 524 pàgines
...course) alone are enough to determine its form : or, as Euclid would express it, two triangles which have two angles of the one equal to two angles of the other, each to each, have the third angles equal, and all the sides of one in the same proportion to the corresponding sides... | |
 | 1842 - 526 pàgines
...course) alone are enough to determine its form : or, as Euclid would express it, two triangles which have two angles of the one equal to two angles of the other, each to each, have the third angles equal, and all the sides of one in the same proportion to the corresponding sides... | |
 | 1842 - 538 pàgines
...alone are • enough to determine its form : or, as Euclid would express it, two triangles which have two angles of the one equal to two angles of the other, each to each, have the third angles equal, and all the sides of one in the same proportion to • the corresponding... | |
 | John Playfair - 1842 - 332 pàgines
...the angles GMK, GMN are both right angles by construction ; wherefore, the triangles GMK, GMN have two angles of the one equal to two angles of the other, and they have also the side GM common, therefore they are equal (26.1.), and the side KM is equal to... | |
 | Euclides - 1842 - 316 pàgines
...by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
 | Charles Hutton - 1843 - 570 pàgines
...(constr.) BAD = AGX, and DE is parallel to AB, we hare ADE = QAD = AGH ; and the triangles ADE, AGH having two angles of the one equal to two angles of the one, aie equi»ngnlar, and therefore similar. Again, since (hyp.) PCH=DCG, we have GCH = DCP = DCF.... | |
 | Euclid, James Thomson - 1845 - 382 pàgines
...equal (const.) to FBD, and that the right angles BED, BFD are equal, the two triangles EBD. FBD have two angles of the one equal to two angles of the other, each to each, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore (I.... | |
 | Euclides - 1845 - 546 pàgines
...right angle FHC equal to the right angle FKC ; '.. ; therefore in the triangles FHC, FKC, there are two angles of the one equal to two angles of the other, each to each ; and the side FC, which is opposite to one of the equal angles in each, is common to both; therefore the... | |
 | Euclid - 1845 - 218 pàgines
...that the right angle B pct Comtr. BED is equal to the right angle BFD; the two triangles EBD, FBD have two angles of the one equal to two angles of the other ; and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
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If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. 
