| Edward Olney - 1872 - 216 pągines
...cos (180° - B') cos (180° - C') . , + sin (180° - B.') sin (180° — C') cos (180° - a"), or, cos A' = — cos B' cos C' + sin B' sin C' cos a", since cos (180° — АО = — cos A', etc. ; and sin (180° — a') = sin a'. Finally, dropping the... | |
| Charles Davies - 1872 - 464 pągines
...value La (2), we have, (20 and now substituting these values of OE, OZ>, and QP, in (1), we h'ave, cos a — cos b cos c + sin b sin c cos A • (3.) Jj the same way, we may deduce, cos b = cos a cos c + sin a sin c cos B • ' (4.) • cos... | |
| Edward Olney - 1872 - 472 pągines
...- AО = cos (180° - B') cos (180° - CO + sin (180° - B') sin (180° — CO cos (180° - «0. or, cos A' = — cos B' cos C' + sin B' sin C' cos a', since cos (180° — AО = — cos A', etc. ; and sin (180° — BO = sin B', etc. Finally, dropping... | |
| 1886 - 418 pągines
...of this relationship may be shown thus : — Any parts between 0 and TT which satisfy the equation cos a = cos b cos c •+• sin b sin c cos A can form a spherical triangle, because cos(S~c), cosa and cos (b + c) would be in descending order... | |
| Harvard University - 1873 - 732 pągines
...Obtain the first two formulas used in the previous question, by means of the following equations: — cos a = cos b cos c + sin b sin c cos A, k sin <(> = sin ft cos A, k cos # = cos 6. 7. Given in a spherical oblique triangle, B = 22° 48',... | |
| Adrien Marie Legendre - 1874 - 500 pągines
...= sin b sin c cos A ; (2.) and now substituting these values of OE, OL, and QP, in ( 1 ), we have, cos a = cos b cos c + sin b sin c cos A • (3.) la the same way, we may deduce, cos b = cos a cos c + sin a sin c cos B • • (4.) cos c... | |
| 1882 - 452 pągines
...sin2a and transposing, 1 — cos a cos b cos c = sin* a + sin b sin c cos A cos a; (1) also cosM = — cos A cos B cos C -\- sin B sin C cos a cos A, whence 1 + cos A cos B cos C '= sin1 A + sin B sin Ccos acos A. (2) Dividing (2) by (1), we... | |
| Aaron Schuyler - 1875 - 284 pągines
...sin c. Substituting the values of OD, OF, and NM, we have cos a = cos b cos e -\~ sin b sin c cos A. In like manner other formulas may be deduced, giving the group, (1) cos a = cos b cos c -f- sin b sin c cos A. (2) cos b = cos a cos c + sin a sin c cos B. (3) cos c — cos a cos b -f- sin... | |
| K.W. Unverzagt - 1876 - 342 pągines
...Scalarund Vectortheil. Uebersetzt lautet die Gleichung cos a = cos c cos b + sin c sin b S (oq . obi), oder cos a = cos b cos c -|- sin b sin c cos A, da S (oc, . ob, ) = — cos (n — A) = cos A ist. (II.) Um den SinussUtz sin a : sin b = sin A : sin... | |
| Henry Nathan Wheeler - 1876 - 204 pągines
...cos AD sin c cos b sin AD . • . cos a = I . cOS AD cOS AD and from [3] tan AD = cos A tan b ; . . . cos a = cos b cos c + sin b sin c cos A, and similarly cos b = cos c cos a + sin c sin a cos B, cos c = cos a cos b + sin a sin 6 cos C. NOTE.... | |
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