 Triangle to equations (I) they become t sin.- A cos. b = cos. B sin. C + sin. B cos. C cos. a ; I sin. A cos. c = cos. C sin. B + sin. C cos. B cos. a. sin. B cos. c = cos. C sin. A + sin. C cos. A cos.  A Treatise on Spherical Astronomy - Pàgina 13per Robert Stawell Ball - 1908 - 506 pàginesVisualització completa - Sobre aquest llibre
 | Hugo Buchholz - 1908 - 496 pàgines
...Projektion von B auf die Ebene AOC erhalten werden: Fig. 136. cos a = cos b cosc + sin b cos c cos A , sin a cos B = cos b sin c — sin b cos c cos // , (IV) sin a sin B = sin A sin A , sin a cos C = sin Ä cos c — cos Ä sin c cos // , sin a sin... | |
 | George Leonard Hosmer - 1910 - 260 pàgines
...The fundamental formulae of spherical trigonometry are cos a = cos b cos c + sin b sin c cos A, [5] sin a cos B = cos b sin c — sin b cos c cos .4 , [6] sin a sin 5 = sin b sin ^4. [7] % If we put A = P, B = S, C = Z, a = 90° - h, b = g0° -... | |
 | Andrew Hall Holt - 1916 - 152 pàgines
...x, y, z, x't y', z', and dividing by r, we have: cos a = cos b • cos c + sin b • sin c • cos A sin a • cos B = cos b • sin c — sin b • cos c • cos A sin a • sin B = sin b • sin A which are the three Fundamental Laws of Spherical Trigonometry. Since we... | |
 | Hugo Buchholz - 1916 - 866 pàgines
...cos B , Q 8 = cos b sin c , 818 §102] 819 cos a = cos b cos c + sin b cos c cos A, sin a cos .S = cos b sin c — sin b cos c cos A , sin a sin B = sin i sin A , sin a cos C = sin S cos c — cos 6 sin c cos A, sin a sin C = sin c sin A .... | |
 | George Neander Bauer, William Ellsworth Brooke - 1917 - 196 pàgines
...cos c cos a + sin a sin c cos /3. Replacing (1 — cos2 c) by sin2 c, and dividing by sin c, we have cos b sin c = sin b cos c cos a + sin a cos /?. Rearranging terms, Also sin b cos y = cos c sin a — sin c cos a cos /?, (4) and sin c cos a =... | |
 | William Carpenter Pendleton Muir - 1918 - 814 pàgines
...— cos d cos < sin L we have -?-/• = 3 ? — = — : ' dL COP a cos Z/ sin t From trigonometry, sin a cos B = cos b sin c — sin b cos c cos 4. Ut = A,B = Z,a = 90e — h,b = 00° — d, c = 90° — L, by substitution, we have cos h cos Z... | |
 | Lancelot Minor Berkely - 1924 - 98 pàgines
...hdh dh _ cos A cos <p — sin A s'm <p cos h d<P ~ sin A cos <p sin h In any spherical triangle ABC, sin a cos B = cos b sin c — sin b cos c cos A. Applying this formula to the triangle PZS, sin ZS cos PZS = cos PS sin PZ — sin PS cos PZ cos ZPS,... | |
 | George Leonard Hosmer - 1925 - 306 pàgines
...small letter. For example, the first two equations would be cos A = cos B cos C + sin B sin C cos a (a) sin A cos b = cos B sin C — sin B cos C cos a. (b) There will also be two other sets of equations for the angles B and C. Equation (1) may be regarded... | |
 | Bund der Sternfreunde, Stuttgart - 1925 - 392 pàgines
...ß = sin b sin <x sin b sin Y = sin c sin ß st« c sin a = sin a sin Y Grundformeln: sin a cos ß = cos b sin c — sin b cos c cos a sin a cos f — cos c sin b — sin c cos b cos a sin b cos Y = cos c sin a — sin c cos a cos ß sin b cos... | |
 | John Charles Duncan - 1926 - 484 pàgines
...triangle can be completely solved by the three fundamental formula cos a = cos b cos c + sin b sin c cos .1 , sin a cos B = cos b sin c — sin b cos c cos A, sin a sin B - sin b sin A. In many cases, the computation is shortened by judicious transformation of these... | |
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