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... for the second term, and the greater for the first ; and in either case multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term.
A Treatise on Plane and Spherical Trigonometry: With Their Most Useful ... - Pągina xxiv
per John Bonnycastle - 1806 - 419 pągines
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## Practical Arithmetic, Uniting the Inductive with the Synthetic Mode of ...

James Bates Thomson - 1846 - 336 pągines
...term, and t/ce other for the first. III. Finally, multiplying the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer...
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## The United States Arithmetic: Designed for Academies and Schools

William Vogdes - 1847 - 256 pągines
...the first and second terms to the same denomination, and the third to the lowest name mentioned. 2. Multiply the second and third terms together, and divide the product by the first; the quotient will be the answer to the question in the same denomination as the third term. 3. If either...
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## Pantology: Or, A Systematic Survey of Human Knowledge ; Proposing a ...

Roswell Park - 1847 - 580 pągines
...first. The question being thus stated, multiply the second and third terms together, and divide their product by the first; and the quotient will be the fourth term, or answer sought. A Compound Proportion, including the solution of problems by what is called the Double...
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## Higher Arithmetic: Or, The Science and Application of Numbers: Combining the ...

James Bates Thomson - 1847 - 422 pągines
...second term, and the other for the first. III. finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer...
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## A treatise on mental arithmetic, in theory and practice

Isaiah Steen - 1848
...that place. Then, the first two terms being reduced to the same simple denomination, when necessary, multiply the second and third terms together, and divide the product by the first term; the quotient is the answer, or fourth proportional required; and it is always of the same denomination...
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## An Arithmetical Dictionary: Or Book of Reference: Comprising a System of ...

William B. Young - 1848 - 297 pągines
...second Terms to the same Jenomination, and to the lowest denomination mentioned in either of them@ ihen multiply the second and third Terms together, and divide the product by the first Term, the result will be the fourth Term or answer, in the same de nomination to which the third Term...
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## A familiar explanation of the higher parts of arithmetic

rev. Frederick Calder - 1848
...and if the third term consist of several denominations, reduce it to the lowest name mentioned. Then multiply the second and third terms together, and divide the product by the first: the quotient will be the answer or fourth term, expressed in the same denomination as that in which...
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## Higher Arithmetic; Or, The Science and Application of Numbers: Combining the ...

James Bates Thomson - 1848 - 422 pągines
...second term, and the other for the first. III. Finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the tame denomination as the third term. PROOF. — Multiply the first term and the answer...
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## Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive ...

Nathan Daboll, David Austin Daboll - 1849 - 249 pągines
...the least of the two remaining numbers fqr the second term, and the greater for the first term ; then multiply' the second and third terms together, and divide the -product by the first term, and the quotient will be the answer in the same name "of the third term EXAMPLES. 1. If 6 yards...
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## Scribner's Engineers' and Mechanics' Companion: Comprising United States ...

J. M. Scribner - 1849 - 264 pągines
...of the two remaining numbers for the second term, and the greater for the first ; and in either case multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term. NOTE. — If the first...
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