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" ... for the second term, and the greater for the first ; and in either case multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term. "
A Treatise on Plane and Spherical Trigonometry: With Their Most Useful ... - Pągina xxiv
per John Bonnycastle - 1806 - 419 pągines
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Adam's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - 1833 - 264 pągines
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as ftie third term. Note 1. If the first...
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The Common School Arithmetic: Prepared for the Use of Academies and Common ...

Charles Davies - 1833 - 270 pągines
...least of the remaining numbers in the first place, but when it is less, place the greater there. Then multiply the second and third terms together and divide the product by the first term : the quo tif.nl will be the fourth term or answer sought, and •will be of the same denomination...
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The North American Arithmetic: for advanced scholars. Part third

Frederick Emerson - 1834 - 288 pągines
...the fourth, make the less of the two remaining terms the first term, and the greater the second: then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. 1. Ifl buy 871 yards of cotton cloth for 78...
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The North American Arithmetic: Part Second, Uniting Oral and Written ...

Frederick Emerson - 1832 - 216 pągines
...than the third, make the less of the two remaining terms the second term, and the greater the first. Multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. If there are different denominations in the...
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The American Student's Guide: Containing a Compendious System of Theoretical ...

George Alfred - 1834 - 312 pągines
...require it. 6. When all the terms of the stating are reduced as above directed, (if necessary) — then multiply the second and third terms together, and divide the product by the^rst term — the quotient will be the fourth term or answer to the question, and of Kke name with...
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Evolution: Or, The Power, and Operation of Numbers, in the Statement, the ...

Thomas Smith (of Liverpool.) - 1835 - 160 pągines
...made it fifteen times too large, divide it by this 15; that is to say, we have the same result if we multiply the second and third terms together, and divide the product by the first. AND THIS is THE RULE ; this, when the terms are properly placed, this MULTIPLYING THE SECOND AND THE THIRD...
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Taplin's improved edition of Walkingame's Tutor's assistant. To which is ...

Francis Walkingame - 1835
...proportion, if necessary, to the same name, and the third to the lowest denomination mentioned in it, then multiply the second and third terms together, and divide the product by the first; the quotient will be the answer to the question in the same denomination the third term was reduced...
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The Teachers' Assistant: Or a System of Practical Arithmetic

Stephen Pike - 1835 - 198 pągines
...and if the third term consist of several denominations, reduce it to its lowest denomination; then, Multiply the second and third terms together, and divide the product by the first term: the quotient will je the answer. Note. — The product of the second and third termsis of he...
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A Practical and Theoretical System of Arithmetic: Containing Several New ...

George Willson - 1836 - 192 pągines
...mentioned in it.* * It is often better to reduce the lower denominations to the decimal of the highest. 3. Multiply the second and third terms together, and...product by the first, and the quotient will be the answer, in that denomination which the third term was left in. In arranging the first two terms, we...
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Arithmetic made easy

A. Turnbull - 1836 - 335 pągines
...these terms would occupy in the statement, as shown above. Now as in every Rule of Three question, we multiply the second and third terms together, and divide the product" by the first, in cases where we work by fractions, the numbers which would form the second and third terms, if the...
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