 | John Bonnycastle - 1848 - 320 pàgines
...less end 48, and the distance of the ends 18 ? Ans. 41733.0144. PROBLEM XXI. Tojlnd the solidity of an hyperboloid. RULE.* To the square of the radius of the base add the square of the middle diameter between the base and the vertex ; and this sum multiplied by the altitude, and the... | |
 | D. M. Knapen - 1849 - 300 pàgines
...contained between two planes perpendicular to the axis. To find the solidity of an hyperboloid : — To the square of the radius of the base add the square of the diameter of a section midway between the base and vertex ; multiply this sum by the altitude, and the product... | |
 | Almon Ticknor - 1849 - 156 pàgines
...Sphere. PROBLEM 29. To find the solidity of a spherical segment with one base. RULE. — To 3 times the square of the radius of the base add the square of the height. Multiply this sum by the height, and the product by -5236 ; the result will be the solidity... | |
 | Charles Davies - 1850 - 218 pàgines
...Bodies. PROBLEM X. To find the solidity of a spherical segment with one base. RULE. 1 . To three times the square of the radius of the base, add the square of the height. II „ Multiply this sum by the height, and the product by the decimal ,5236, the result will... | |
 | Charles Davies - 1850 - 238 pàgines
...Bodies. PROBLEM X. To find the solidity of a spherical segment with one base. RULE. I. To three times the square of the radius of the base, add the square of the height. II. Multiply this sum by the height, and the product by the decimal ,5236, the result will... | |
 | John Radford Young - 1850 - 294 pàgines
...content of the middle zone. Or, without employing the radius of the sphere, RULE III — To six times the square of the radius of the base add the square of the height. Multiply the sum by the height, and by -5236, and the product will be the solid content. EXAMPLES.... | |
 | Oliver Byrne - 1851 - 310 pàgines
...18 x -3927 = 76752 x -3927 = 30140-5104 = the solidity. To find the solidity of an hyperboloid. — To the square of the radius of the base add the square of the middle diameter between the base and the vertex, and this sum multiplied by the altitude, and the product... | |
 | Charles Davies - 1855 - 340 pàgines
...Round BodiesPROBLEM XTo find the solidity of a spherical segment with one baseRULE I To three times the square of the radius of the base, add the square of the heightII Multiply this sum by the height, and the product by the decimal -5236, the result will be... | |
 | Oliver Byrne - 1863 - 600 pàgines
...18 x -3927 = 76752 x -3927 = 30140-5104 = the solidity. To find the solidity of an hyperboloid. — To the square of the radius of the base add the square of the middle diameter between the base and the vertex, and this sum multiplied by the altitude, and the product... | |
 | Septimus Tebay - 1868 - 168 pàgines
...306 18 42 36 18o 8 3 11 1987 662 94 (2) When the dimensions of the segment are given: To three times the square of the radius of the base add the square of the depth ; multiply the sum by the depth ; then multiply by 11 and divide by 21. TM 6 Ex. Find the solidity... | |
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To find the solidity of a hyperbolic conoid, or otherwise called a hyperboloid. RULE. To the square of the radius of the base, add the square of the diameter... 
