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" KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC. "
The New American Practical Navigator; Being an Epitome of Navigation ... - Pàgina 11
per Nathaniel Bowditch - 1846 - 451 pàgines
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A Manual of Surveying for India, Detailing the Mode of Operations on the ...

Sir Henry Edward Landor Thuillier - 1851 - 826 pàgines
...ABDE + ACGF the sum of the squares, = BKLH = KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on EC. QED Cor. 1; The hypothenuse of a right-angled triangle may be found by having the other two sides...
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The Elements of Euclid: With Many Additional Propositions ..., Part 1

Euclid - 1853 - 176 pàgines
...square on AE is equal in area to twice the square on AD together with twice the square on DE (rf); therefore the sum of the squares on AB and AC is equal in area to twice the ^ square on BE, twice the square on DE, and twice the square on AD taken together....
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Exercises on Euclid and in Modern Geometry

James McDowell - 1878 - 310 pàgines
...the sides of the triangle ABC meet in <?. Since AD bisects the side BC in D, therefore by (41), twice the sum of the squares on AB and AC is equal to four times the squares on AD and DB, that is, to four tunes the square on AD to- . gether with the...
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New American Practical Navigator

1880 - 880 pàgines
...the parallelograms BKLH and KCML; but the sum of these parallelograms is equal to the square BCMH ; therefore the sum of the squares on AB and AC is equal...may easily find the other leg, by taking the square ol the given leg from the square of the hypotenuse ; the square root of the remainder will be the sought...
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The American Practical Navigator: Being an Epitome of Navigation and ...

Nathaniel Bowditch - 1888 - 704 pàgines
...the parallelograms BKLH and KCML; but the sum of these parallelogram? is equal to the square BCMH; therefore the sum of the squares on AB and AC is equal to the square on BC. Cor. Hence, in any right angled triangle, if we have the hypotenuse and one of the legs, we may easily find the other...
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Calendar, Part 3

University of Calcutta - 1908 - 562 pàgines
...CB, and twice the rectangle AC, CD. ABC is a triangle whose side BC is bisected at D ; show that 4 the sum of the squares on AB and AC is equal to twice the sum of the squares on AD and DB. 9. Show how to bisect an arc of a circle. 4 10. Inscribe...
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Fundamentals of High School Mathematics: A Textbook Designed to Follow ...

Harold Ordway Rugg, John Roscoe Clark - 1919 - 392 pàgines
...same unit 5 times. By constructing squares on the sides of the triangle, you can see by counting that the sum of the squares on AB and AC is equal to the square on BC. To test this further, the pupil should construct a right triangle with the base 12 units and the altitude...
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Mathematics For Technical students

S. N. Forrest - 1947 - 444 pàgines
...hypotenuse. Now figures 1, 2, 3, 4 and 5 will fit together exactly to make the square on BC, showing that the sum of the squares on AB and AC is equal to the square onBC. Fig. 128 shows another right-angled triangle ABC. Again, figures 1, 2, 3, 4 and 5 fit exactly...
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Sessional Papers, Volum 52,Edició 19

1917 - 1134 pàgines
...the base. (Z>) If a straight line BO is bisected at D, and Л is any point in BC or BC produced, then the sum of the squares on AB and AC is equal to twice the sum of the squares on ВП and AD. 7. (a) If two triangles have an angle of the one equal...
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