 | Euclides - 1856
...with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. XVI. If two triangles have two sides of the one equal to two sides of the other, each to each, and... | |
 | William Mitchell Gillespie - 1857 - 524 pągines
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles is equal to twice as many right angles, as the figure has sides less two ; since the figure can be divided into that number of triangles. Hence this common rule. "... | |
 | Adrien Marie Legendre - 1857 - 448 pągines
...equal to twice as many right angles as the polygon has sides. Again, the sum of all the interior angles is equal to twice as many right angles as the figure has sides, less four right angles (p. 26). Hence, the interior angles plus four right angles, is equal to twice... | |
 | Elias Loomis - 1858 - 234 pągines
...that is, together with four right angles (Prop. V., Cor. 2). Therefore the angles of the polygon are equal to twice as many right angles as the figure has sides, wanting four right angles. Cor. 1. The sum of the angles of a quadrilateral is four right angles ; of a pentagon,... | |
 | W. Davis Haskoll - 1858 - 324 pągines
...and in an irregular polygon they may be all unequal. The interior angles of a polygon are together equal to twice as many right angles as the figure has sides, less four. On this is based the theory of the traverse, of which further explanation will be given... | |
 | Charles Hutton - 1860 - 895 pągines
...Hence it lotIons that the sum of all the inward angles of the polygon alone, A -f- В — -f. D -f. E, is equal to twice as many right angles as the figure has side*, «am”ng the said tour right angles- Q. !•'- D. THEOREM xx. When every side of any figure... | |
 | Royal college of surgeons of England - 1860
...two right angles ; and all the angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 6. The opposite sides and angles of parallelograms are equal to one another, and the diameter bisects... | |
 | 1860
...must be aliquot parts of the circle or of four right angles. All the angles of any such figure are equal to twice as many right angles as the figure has sides minus four right angles, or if « be the number of sides, the sum of all the angles is (2n — 4) right... | |
 | W J. Dickinson - 1879 - 36 pągines
...produced to meet, the angles formed by these lines, together with eight right angles, are together equal to twice as many right angles as the figure has sides. Same proposition. ABC is a triangle right-angled at A, and the angle B is double of the angle C. Show... | |
 | Michael McDermott - 1879 - 586 pągines
...future operations. 213. All the interior angles of any polygon, together with four right angles, are equal to twice as many right angles as the figure has sides. Example. Interior angles A, B, C, D, E, F = n° 4 right angles, 860 Sum = n° + 360° Namber of sides... | |
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