 | William Smyth - 1858 - 344 pągines
...whole divisor by the term of the quotient just found, and subtract the result from the dividend ; 3°. divide the first term of the remainder by the first term of the divisor, the result will be the second term of the quotient, 4°. multiply the whole divisor by the... | |
 | Charles Davies - 1859 - 324 pągines
...Multiply t/ie divisor by this term of the quotient, and subtract the product from the dividend: Ш. Divide the first term of the remainder by the first term of the divisor, for the second term of the quotient. Multiply the divisor by this term, and subtract the product... | |
 | Charles Davies - 1860 - 412 pągines
...the quotient ; multiply the divisor by this term and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, for the second term of the quotient ; multiply the divisor by this second term, and subtract... | |
 | Charles Davies - 1861 - 322 pągines
...quotient ; multiply the divisor by thi2 tern, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient; multiply the divisor by the second term, and... | |
 | William Smyth - 1861 - 496 pągines
...whole divisor by the term of the quotient just found, and subtract the result from the dividend ; 3°. divide the first term of the remainder by the first term of ike divisor, the result will be the second term of the quotient , 4°. multiply the whole divisor by... | |
 | Elias Loomis - 1864 - 386 pągines
...the quotient. 3. Multiply the divisor by this term, and subtract the product from the dividend. 4. Divide the first term of the remainder by the first term of the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term,... | |
 | Paul Allen Towne - 1865 - 314 pągines
...the whole of the root, and write the result to the left of the remainder, as a part of the divisor; divide the first term of the remainder by the first term of the partial divisor, and place the result as the third term of the root, and also at the right of the partial... | |
 | Joseph Ray - 1866 - 252 pągines
...the product from the remainder. 4. Double the terms of the root already found, for a partial divisor, and divide the first term of the remainder by the first term of the divisor, and annex the result both to the root and the partial divisor. Multiply the divisor thus increased,... | |
 | Joseph Ray - 1866 - 250 pągines
...the product from the remainder. 4. Double the terms of the root already found, for a partial divisor, and divide the first term of the remainder by the first term of the divisor, and annex the result both to the root and the partial divisor. Multiply the divisor thus increased,... | |
 | Joseph Ray - 1852 - 422 pągines
...term of the quotient. Multiply the divisor ty this term, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor; the result will be the second term of the quotient. Multiply the divisor by this term, and... | |
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Then divide the first term of the remainder by the first term of the divisor... 
