 | Charles Davies - 1842 - 368 pągines
...the quotient; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by this second term, and... | |
 | George Roberts Perkins - 1842 - 370 pągines
...the quotient; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by this second term, and... | |
 | Charles Davies - 1842 - 284 pągines
...quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by the second term, and... | |
 | 1842 - 538 pągines
...for the square root of numbers in every point but this, that the new term is always found by dividing the first term of the remainder by the first term of the divisor. A couple of examples will suffice. Let it ba required to find the square root of 1 +2x+3x!+<lx*+... | |
 | James Bates Thomson - 1844 - 272 pągines
...highest next, ftc. II. Take the root of the first term, for the first term of the required root : III. Subtract the power from the given quantity, and divide...term of the remainder by the first term of the root in volved to the next inferior power and multiplied by the index of the given power ;* the quotient... | |
 | James Bates Thomson - 1844 - 272 pągines
...following KULE. I. Jlrrange the terms of the given quantity according to the powers of one of the letters, take the root of the first term, for the first term of the required root, and subtract the power from the given quantity. II. Bring down two other terms for a dividend. Divide... | |
 | Alexander Ingram - 1844 - 262 pągines
...2a6 + 6a+2ac+26c+c2) = a+b + c. 7. ' 8. TO EXTRACT ANY OTHER ROOT. Arrange the terms as in Division ; take the root of the first term for the first term of the root ; raise this root to a power less by one than the given power, and multiply it by the name of... | |
 | James Thomson - 1844 - 328 pągines
...root of the first term will be the first term of the required root. Take the nth power of this term from the given quantity, and divide the first term of the remainder by n times the term already found, raised to the power n — 1 ; the quotient will be the next term of... | |
 | William Scott - 1844 - 568 pągines
...term of the quotient. Multiply the divisor by this term, and subtract the product from the quotient. . Divide the first term of the remainder by the first term of the divisor; the result is the second term of the quotient. Multiply the divisor by the second term of... | |
 | Ormsby MacKnight Mitchel - 1845 - 308 pągines
...first term of the quotient, and subtract the product from the dividend, and oring down the remainder. Divide the first term of the remainder by the first term of the divisor, and the quotient will be the second term of the quotient ; multiply the divisor by the second... | |
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Then divide the first term of the remainder by the first term of the divisor... 
