 | Jacques Ozanam - 1803 - 548 pàgines
...to determine the triangle. PROB. xxxu. The base of a triangle, the sum of the two other sides, and the line drawn from the vertex to the middle of the base, being given; to determine the triangle. PKOB. xxxv. Given the three lines drawn from the angles of... | |
 | Charles Hutton - 1811 - 406 pàgines
...with Double the Square of the Half Base, is Equal to the Sum of the Squares of the other Two Sides. Let ABC be a triangle, and CD the line drawn from...CB, be equal to twice the sum of the squares of CD, BD; or Ac* -f CB* = 2CD* + 2DB*. For, let CE be perpendicular to the base AB. Then, since (by th. 36)... | |
 | Charles Hutton - 1812 - 620 pàgines
...Double the Square of the Half Base, is Equal to the Sum of the Squares oi the other Two Sides. Let A DC be a triangle, and CD the line drawn from the vertex to the middle of the base AB, dividing it into the two equal parts AD, DB ; then will the sura of the squares of AC, CB, be equal... | |
 | Charles Hutton - 1816 - 610 pàgines
...be a triangle, and CD the line drawn from the vertex to the middle of the base AB, dividing it into two equal parts AD DB ; then will the sum of the squares...CB, be equal to twice the sum of the squares of CD, BD j or Ac2 + CBI= 2CD» -f SDB*. -A. DEB For, let CE be perpendicular to the base AB. Then, since... | |
 | Charles Hutton - 1818 - 646 pàgines
...with Double the Square of the half Base, is Equal to the Sum of the Squares of the other Two Sides. Let ABC be a triangle, and CD the line drawn from the vertex to the middle of the base AB, dividing it into two equal parts AD, DB ; then will the sum of the squares of AC, CB, be equal to twice... | |
 | Sir John Leslie - 1820 - 488 pàgines
...this proposition it might be easily shown that the two sides of a triangle are greater than double the line drawn from the vertex to the middle of the base. For, suppose E to be that middle point, and BE being produced till EF be equal to it, and let AF be... | |
 | Charles Hutton - 1822 - 616 pàgines
...Doable the Square ef the Half Base, is equal to the Sum of the Square* of the other Two Sides. Let ADC be a triangle, and CD the line drawn from the vertex to the middle of <~ the bast AB, dividing it into two equal parts AD, DB ; tnen will the -sum of the squares of AC, CB, be... | |
 | Charles Hutton - 1825 - 608 pàgines
...Double the Square of the Half Base, is equal to the Sum of the Square* of thp other Two Sides. Let ADC be a triangle, and CD the line drawn from the vertex to the middle of y the base AB, dividing it into two equal parts AD, DB ; then will the sum of the squares of AC, CB,... | |
 | Charles Hutton - 1831 - 632 pàgines
...with double the square of the half base, is equal to the sum of the squares of the other two sides. Let ABC be a triangle, and CD the line drawn from...parts AD, DB ; then will the sum of the squares of AC, ев, be equal to twice the sum of the squares of CD, AD ; or лс3 + cB' = 2cD3 + 2AD'. A DEB For... | |
 | Charles Hutton - 1831 - 660 pàgines
...THEOREM!. double the square of the half base, is equal to the sum of the squares of the other two sides. Let ABC be a triangle, and CD the line drawn from the vertex to the middle of the base лв, bisecting it into the two equal parts AD, DB ; then will the sum of the squares of AC, ев,... | |
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AB, bisecting it into the two equal parts AD, DB ; then will the sum of the squares of AC, CB, be equal to twice the sum of the squares of CD, BD; or Ac* -f CB* = 2CD* + 2DB*. 
