 | James Thompson - 1808 - 176 pàgines
...area of a trafiezoid, or quadrangle, <u'o cf •whose opposite sides are parallel. RULE — Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product •will be the area. EXAMPLES. 13. Required the area of a trapezoid whose parallel... | |
 | Matthew Iley - 1820 - 512 pàgines
...Area of a Quadrilateral wherein two unequal Sides are Parallel to one another. RULE. Multiply half the sum of the parallel sides by the perpendicular distance between them, and the product will be the area. Let ABCD be a quadrilateral, wherein AC and BD are parallel but unequal;... | |
 | Anthony Nesbit - 1824 - 476 pàgines
...is its area ? Ans. 1131^.2 in. 9 pa. PROBLEM VIII. To find the area of a Irapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Or, half the sum of the sides multiplied by their distance will... | |
 | Thomas Hornby (land surveyor.) - 1827 - 318 pàgines
...00000000 2.40000 40 16.00000 Ans. 0A. 2n. 16p. PROBLEM 3. To find the Area of a Trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. EXAMPLE. Required the area of the trapezoid AB CD, whose parallel... | |
 | John Bonnycastle - 1829 - 256 pàgines
...the area of a trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides... | |
 | Edinburgh encyclopaedia - 1830 - 856 pàgines
...trapezoid is a quadrilateral, of which two opposite sides are parallel but not equal. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product is the area. In the trapezoid ABCD, draw the diagonal AC, and from its extremities... | |
 | Tobias Ostrander - 1834 - 136 pàgines
...EXAMPLES. 1. 24,46 + 38,40 = 62,86 chains the sum of the two parallel sides ; then 62,86 X 16,2 = 1018,332 the product of the sum of the parallel sides by the perpendicular ; then 2)1018,332 = 509,166 square chains ; then 10)509,166 = 50,9166 acres = 50 acres, 3 roods, and... | |
 | William Galbraith - 1834 - 454 pàgines
...Trapezium. — Multiply the base into half the sum of the perpendiculars. 4. Trapezoid. — Multiply half the sum of the parallel sides by the perpendicular distance between them. fi. Irregular Polygon. — Divide it into triangles, find their areas, the sum of these will be the... | |
 | Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 pàgines
...16s + 122 = 20, the length of the hypotenuse. HoW do you find the area of a trapezoid ? Multiply half the sum of the parallel sides by the perpendicular distance between them, and the product will be the area of the trapezoid. What is the area of a trapezoid, its parallel sides... | |
 | Charles Davies - 1840 - 262 pàgines
...the breadth of the Ans. 77,8875 feet. PROBLEM VI. 13. To find the area of a trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and then divide the product by two : — the quotient will be the area. EXAMPLES. DC 1. Required the... | |
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The content of a Trapezoid equals half the product of the sum of the parallel sides by the perpendicular distance between them. 
