 | James Edward Oliver - 1881 - 120 pągines
...all cases : Take each of the two given parts in turn for middle part, and apply that one of Napier's rules which brings in the other given part. Take the...used. CASE 1. Given p and q, the two sides about the right angle, then: sing = tanp cotp, .'. cotp = cotp sing; sin p = tang cot Q, .'. cot Q = sin p cot... | |
 | James Edward Oliver - 1881 - 140 pągines
...middle part, and apply that one of Napier's rules which brings in both the given parts. The whole wo11k requires but nine logarithms, or seven without the...used. CASE 1 . Given p and q, the two sides about the right angle, then: sinq = tanpcotp, .'. cot p = cot p sing; sinp = tan q cot Q, . • . cot Q = sinp... | |
 | James Edward Oliver - 1889 - 178 pągines
...these functions, ie, not the final results ; more perfect checks are got from the general formulas. by not more than three units in the last decimal place,...discrepancy exist, the mean of the two values may be used. THE PARTS ALL POSITIVE AND LESS THAN TWO RIGHT ANGLES. (a) Given p, q, the two sides about the right... | |
 | James Edward Oliver - 1890 - 186 pągines
...functions, ie, not the final results ; more perfect checks are got from the general formulas. The check is applied to the sine of the part last found ; if the...discrepancy exist, the mean of the two values may be used. THE. PAKTS ALL POSITIVE AND LESS THAN TWO RIGHT ANGLES. (a) Given p, g, the two sides about the right... | |
 | George William Jones - 1896 - 216 pągines
...of the general formulae which involve the three computed parts and one or more of the given parts. is probably right, since the defects of the tables...discrepancy exist, the mean of the two values may be used. These rules involve only the interior angles : for the general solution of the right triangle the formulae... | |
 | Pitt Durfee - 1900 - 340 pągines
...of the general formulae which involve the three computed parts and one or more of the given parts. is probably right, since the defects of the tables...discrepancy exist, the mean of the two values may be used. These rules involve only the interior angles : for the general solution of the right triangle the formulae... | |
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The whole wo11k requires but nine logarithms, or seven without the check, since two of the logarithmic functions are used twice over. The check is to be applied to the sine of the part last found. If the two values got for this sine, natural or logarithmic,... 