 | Abel Flint - 1830 - 322 pàgines
...sides and the logarithms of the three remainders be added together, the num. » Better expressed thus. From half the sum of the sides subtract each side separately. Multiply the half sum and the several remainders together, and the square root of the product will be the area.... | |
 | Abel Flint - 1835 - 368 pàgines
...: it follows, that if the logarithm of the half sum of the three sides and * Better expressed thus. From half the sum of the sides subtract each side separately. Multiply the half sum and the several remainders together, and, the logarithms of the three remainders be added... | |
 | John Hind - 1837 - 584 pàgines
...notation of the last example, we have the area - £ AB x CD C 2 = - x - \/s (s — «)(« — b) (s — c) From half the sum of the sides, subtract each side separately: multiply the half sum and the three remainders together, and the square root of the product will be the area. Ex.... | |
 | John Hind - 1855 - 540 pàgines
...(* - 6) (A - с) .-* ОС = -У/С*- *)(*-*)(*-<:). Hence, the Rule enunciated at length will be : From half the sum of the sides, subtract each side separately; multiply the half-sum and the three remainders together, and the square root of the product will be the area. Ex.... | |
 | Septimus Tebay - 1868 - 168 pàgines
...20-35 p. THE TRIANGLE CONTINUED. IX. TO find the area of a triangle when the three sides are given. From half the sum of the sides subtract each side separately; multiply the half sum and the three remainders together, and extract the square root. Ex. 1. Find the area of a... | |
 | Albert Newton Raub - 1877 - 348 pàgines
...3 in. high, at 6 cts. a square foot. Ans. 2. When the three sides of a triangle are given, to find the area, from half the sum of the sides subtract each side separately ; multiply the three remainders together, and this product by the half sum of the aides ; the square root of the product... | |
 | Horatio Nelson Robinson - 1878 - 564 pàgines
...the included angle 61° 12' ? RULE 3. — "When the three sides of a triangle are known : From one half the sum of the sides, subtract each side separately...continued product of these remainders ~by the half sum y the square root of the product will be the area, required. Demonstration. Let A represent the area... | |
 | James Edward Oliver - 1881 - 140 pàgines
...smA SIUB 128] »"=: — = a SmB S1° °a smA ~ 6sincsinA csinAsins So, pt = -. ) and p, = : sine sinc CASE 3. Given the three sides, a, b, c: (1) For the...perpendicular falls. For, v K = ^a6sinc; [126 and vsinc = 2sin4/ccos^c [60 = ^(S~albS~b}^^ [1°9'110 129] .'. K= Vs(sa) (s-6) (s — c), , --K So, -P'... | |
 | James Edward Oliver - 1881 - 120 pàgines
...в sin с 128] р° = — — : a smA _ &sincsinA ., csinAsinB So, pb = : i and »c = ; sinB J sinc CASE 3. Given the three sides, a, b, c: (1) For the...the side on which the perpendicular falls. For, v K = ^a&sinc; [126 and •.'sinc = 2sin^ccos^c [60 ii-JO [109, 110 129] .'. к = V s (s - a) (s —b)... | |
 | Stewart W. and co - 1884 - 272 pàgines
...respectively ? Ans. 278r*r feet. V. To find the area of a triangle when the three aides are given. RULE. From half the sum of the sides subtract each side separately. Multiply the half-sum of the sides by the differences thus found, and the area will be the square root of the product,... | |
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For the area, from half the sum of the sides subtract each side separately, multiply the continued product of these remainders by the half sum, and take the square root of the product. 
