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" RULE. From half the sum of the three sides subtract each side severally. "
The Theory and Practice of Surveying: Containing All the Instructions ... - Pągina 197
per Robert Gibson - 1811 - 508 pągines
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A Treatise of Practical Surveying: Which is Demonstrated from Its First ...

Robert Gibson - 1806 - 486 pągines
...Hence the following problem will be evident. PROBLEM VIII. Three sides of a plane triangle given t0 find the area. RULE. From half the sum of the three...the logarithms of half the sum and three remainders, anil half their total will be the logarithm of the area : or, take the square root of the continued...
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The Tutor's Guide: Being a Complete System of Arithmetic; with Various ...

Charles Vyse - 1806 - 342 pągines
...let at per Acre ? Case 2. When the three Sides of a Triangle are given, to find the Area. RULE. 3. From Half the Sum of the three Sides subtract each Side severally ; multiply the Half Sum and the three Remainders continually together, and the Square Root of the last...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1814 - 558 pągines
...a filant Mangle given to Jlnd the areq. RULE. From half the sum of the three sides subtract •ach side severally ; take the logarithms of half the sum...be the logarithm of the area : or, take the square root of the continued product of the half sum and three remainders for the area. . EXAMPLES. Pi. S.jg....
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A Treatise on Surveying, Containing the Theory and Practice: To which is ...

John Gummere - 1814 - 398 pągines
...48° 15'? Ans. 6A. 3R. 18P. PROBLE To find the area of a triangle, when the three sides are. given. % RULE; From half the sum of the three sides subtract each side severally ; multiply the half sum and the three remainders contiuually together, and the square root of the last...
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The Tutor's Guide: Being a Complete System of Arithmetic; with Various ...

Charles Vyse - 1815 - 340 pągines
...let at per acre ? Case 2. When the three sides of a triangle are given, to find the area. i RULE. 3. From half the sum of the three sides subtract each side severally ; multiply the half cum and the three remainders continually together, and the square root of the Iast...
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A Treatise on Practical Surveying: Which is Demonstrated from Its First ...

Robert Gibson - 1818 - 502 pągines
...the area. Q. ED Hence the following problem will be evident. PROB. VIII. Tlie three sides of a plane triangle given, to find the area. RULE. From half...subtract each side severally ; take the logarithms of the half sum and three remainders, and half their total will be the logarithm of the area : or take...
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A Treatise on Practical Mensuration in Eight Parts ...

Anthony Nesbit - 1824 - 476 pągines
...£6 4*. 7 \d. , PROBLEM V. To find the area of a triangle, the three sides only of which are given. RULE. From half the sum of the three sides subtract each side severally ; multiply the half sum and the three remainders continually together; and the square root of the last...
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A Treatise on Surveying: Containing the Theory and Practice: to which is ...

John Gummere - 1828 - 404 pągines
...and.48°15'? Ans. 6 A. 3R. 18 P. PROBLEM V. To find the. area of a triangle when the three sides are given. From half the sum of the three sides subtract each side severally; multiply the half sum and the three remainders continually together, and the square root of the last...
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A Short System of Practical Arithmetic: Compiled from the Best Authorities ...

William Kinne - 1829 - 246 pągines
...true right-angle. RULE 2. — To find the area of any triangle when the three sides only are given, RULE. — From half the sum of the three sides' subtract each side severally ; multiply these three remainders and the said half sum continually together; then the square root...
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An Introduction to Mensuration and Practical Geometry

John Bonnycastle - 1829 - 256 pągines
...102. 5/e. PROBLEM III. To find the area of a triangle whose three sides only are given. RULE.* . 1 . From half the sum of the three sides subtract each side severally. * Demon. Let AC— a, ±3=b, uc=c, and AD=a:; (See preceding fig.) Then, since BD=&— x, we shall...
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