 | Euclides - 1840 - 192 pàgines
...triangle also bisects the base, the triangle must be isosceles. 16. In a right-angled triangle, the line drawn from the vertex of the right angle to the middle point of the base, is • equal to half of the base. (Pr.32.) 17. In a right-angled triangle, the angle contained... | |
 | William Desborough Cooley - 1840 - 106 pàgines
...unequal ; and the triangle BAC is isosceles. PROP. XVI. In a right-angled triangle (ABC), the line (AD) drawn from the vertex of the right angle to the middle point of the base, is equal to half of the base. For if AD were greater than DC, then Z. ACD would be greater than... | |
 | Webster Wells - 1886 - 392 pàgines
...greater than the sum of the squares of the adjacent sides. 70. In a right triangle ABC, BC2=3AC2. If CD is drawn from the vertex of the right angle to the middle point of AB, prove that Z ACD = 60°. 71. If D is the middle point of the side BC of the right triangle ABC,... | |
 | George Irving Hopkins - 1891 - 204 pàgines
...one base of a trapezoid are equal, the angles at the other base are also equal. 157. The line joining the vertex of the right angle to the middle point of the hypothenuse in a right triangle is equal to one-half the hypothenuse. 158. The lines which join the... | |
 | Joe Garner Estill - 1896 - 186 pàgines
...difference of the angles B and C—Cornell. 11. Show that in any right-angled triangle the distance from the vertex of the right angle to the middle point of the hypotenuse is equal to one-half the hypotenuse.— School of Mine ft. 12. If D is the middle point of the side... | |
 | Joe Garner Estill - 1896 - 168 pàgines
...difference of the angles B and C. — Cornell. 11. Show that in any right-angled triangle the distance from the vertex of the right angle to the middle point of the hypotenuse is equal to one-half the hypotenuse. — School of Mines. 12. If D is the middle point of the side... | |
 | Webster Wells - 1898 - 264 pàgines
...= AF 2 : EF 2 ; then, we have AD: CD = AG :EG.) 70. In right triangle ABC, BC' 2 = 3 AC*. If CD be drawn from the vertex of the right angle to the middle point of AB, prove ZACD equal to 60°. (Ex. 83, p. 69.) 71. If D is the middle point of side BC of right triangle... | |
 | William James Milne - 1899 - 258 pàgines
...times the square upon half the line bisected. Ex. 571. In the right triangle ABC, BC* = 3 AC2. If CD is drawn from the vertex of the right angle to the middle point of AB, angle ACD equals 60°. Ex. 572. If ACB and ADB are two angles inscribed in a semicircle, and AE... | |
 | William James Milne - 1899 - 404 pàgines
...the square upon half the line bisected. • Ex. 571. In the right triangle ABC, BC* = 3 AC1. If CD is drawn from the vertex of the right angle to the middle point of AB, angle ACD equals 60°. » Ex. 573. li lines are drawn perpendicular to the diagonals of a square... | |
 | William James Milne - 1899 - 326 pàgines
...= 4DC¡ + BC2-(BCí + DC?); т^а ÍTT3 o r¿f& Ex. 571. In the right triangle ABC, BC2=3AC2. If CD is drawn from the vertex of the right angle to the middle point of AB, angle A CD equals 60°. Proof. ÄB2 = BC2 + Ä(? = ZÄC2 + ÄC2-iÄC!2i AB = Ï AC, and J AB, or... | |
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CD is drawn from the vertex of the right angle to the middle point of AB, angle ACD equals 60°. 
