 | Jeremiah Day - 1815 - 172 pągines
...removed from under the radical sign. (Alg.271.) Therefore, S= Vhx (ha) x (hb) X (hc) 222. For finding the area of a triangle, then, when the three sides...remainders ; and •extract the square root of the product. SECTIOK VIII. COMPUTATION OF THE CANON. A 22^ TPHE trigonometrical canon is a set of table* RT' ' •*-... | |
 | Jeremiah Day - 1815 - 388 pągines
...angle included by either of the pairs of side* multiplied together. Or, II. From half the sum of all the sides, subtract each side severally, multiply together the half sum and the four remainders, and extract the square root of the product. If the sides are a, b, c, and d; and if... | |
 | Jeremiah Day - 1824 - 440 pągines
...factors. Let A=j(«-r-fe+c) half the sum of the sides. Then S = Sh-X.(ha)-X.(hb)x(hc) 222. For finding the area of a triangle, then, when the three sides...the sides, subtract each side severally ; multiply togetfar the half sum and the three remainders } and . retract the square root of the product. , SECTION... | |
 | Jeremiah Day - 1831 - 520 pągines
...these factors. Let A=£(a+6+c) half the sum of the sides. Then S = Shx(ha)x(hb)x(hc) 222. For finding the area of a triangle, then, when the three sides...remainders; and extract the square root of the product. -, > -/ J i SECTION VIII. COMPUTATION OF THE CANON. ART. 223. THE trigonometrical canon is a set of... | |
 | Jeremiah Day - 1831 - 394 pągines
...directly obtained, by the following method. RULE II. When the three sides are given, from half their sum subtract each side severally, multiply together the...remainders, and extract the square root of the product. If the sides of the triangle are a, 6, and c, and if &=half their sum, then The area—Vh X (A- a)... | |
 | Jeremiah Day - 1831 - 418 pągines
...directly obtained, by the follow^g method. RULE II. When the three sides are given, from half their sum subtract each side severally, multiply together the...remainders, and extract the square root of the product. If the sides of the triangle are a, 6, and c, and if A=half their sum, then The area=VAX(Aa)X(A—... | |
 | Samuel YOUNG (of Manchester.) - 1833 - 272 pągines
...angular point 36 perches. How many acres does it contain ? When the three sides only are given. RULE 2. From half the sum of the sides subtract each side severally : multiply the half sum and the three Remainders continually together, and the square root of their Product will... | |
 | Francis Walkingame - 1833 - 204 pągines
...ridge to the middle of the base, 9 feet 4 inches ? ADB RULE 2. When the three sides only are given. — From half the sum of the sides subtract each side severally: multiply the half sum and the three remainders continually together ; and the square root of their product will... | |
 | Jeremiah Day - 1836 - 418 pągines
...these factors. Let h=^(a+b+c) half the sum of the sides. Then S = v/Ax(Aa)x(A-6)x(Ac) 222. For finding the area of a triangle, then, when the three sides are given, we have this general rule ; From half thf turn of the sides, subtract each side severally ; multiply together the half sum and the three... | |
 | 1836 - 488 pągines
...three sides are given, from half their sum, subtract each side severally, multiply together half the sum and the three remainders, and extract the square root of the product. To ßnd the area of a trapezoid. Multiply half the sum of the parallel sides into their perpendicular... | |
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From half the sum of the three sides subtract each side separately ; multiply together the half sum and the three remainders, and extract the square root of the product. 
